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10y^2-1y-2=0
a = 10; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·10·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-9}{2*10}=\frac{-8}{20} =-2/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+9}{2*10}=\frac{10}{20} =1/2 $
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